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=2Y^2-7Y-10
We move all terms to the left:
-(2Y^2-7Y-10)=0
We get rid of parentheses
-2Y^2+7Y+10=0
a = -2; b = 7; c = +10;
Δ = b2-4ac
Δ = 72-4·(-2)·10
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{129}}{2*-2}=\frac{-7-\sqrt{129}}{-4} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{129}}{2*-2}=\frac{-7+\sqrt{129}}{-4} $
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